function

y = ax3+bx2+cx+d

y =−b+22b2−6ac/3a   

x=2

ax3+bx2+cx+d−−b+22b2−6ac/3a= 0

(x−b+22b2−6ac/3a)2(x−α) = 0

ax3+bx2+cx+d−−b−22b2−6ac/3a= 0

(x−b−22b2−6ac/3a)2(x−β) = 0 

 

x=1

y = ax3+bx2+cx+d

y=m

ax3+bx2+cx+d−m = 0

(x−γ)(a'x2+b'x2+c') = 0

b'2−4a'c'<0

 

         T.theodor          2022.8.18