y = ax3+bx2+cx+d
y =−b+2√2b2−6ac3a
x=2
ax3+bx2+cx+d−−b+2√2b2−6ac3a= 0
(x−−b+2√2b2−6ac3a)2(x−α) = 0
ax3+bx2+cx+d−−b−2√2b2−6ac3a= 0
(x−−b−2√2b2−6ac3a)2(x−β) = 0
x=1
y = ax3+bx2+cx+d
y=m
ax3+bx2+cx+d−m = 0
(x−γ)(a'x2+b'x2+c') = 0
b'2−4a'c'<0
T.theodor 2022.8.18