B(z1,z2) ≠ B(z2,z1) z1 = a+bi z2 = c+di f(x) = tz1 −1(1−t)z2 −1 T.theodor 2022.9.26.
Π 1−1/ns T.theodor 2022.9.26.
(1−1/2s)ζ(s) = (1−1/2s)+… ζ(s) ≠ Πp 1/1−p-s T.theodor 2022.9.26.
Quote saved.
Login to quote this blog
Failed to save quote. Please try again later.
You cannot quote because this article is private.