1+1/3+1/6… = 2−2/n+1 T.theodor 2022.9.28.
ak= (−1) n−1n = [n+1/2]([n+1/2]+1)−[n+1/2]−[n/2]([n/2]+1) T.theodor 2022.9.28.
log(1+x) ≠ Σ(−1)n+1/nxn T.heodor 2022.9.27.
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