△PF1F2=√4a(√a2−b2+a)((2√a2−b2+2a−a2(√a2−b2+t)2+b2(a2−t2)/a) (2√a2−b2+2a−a2(√a2−b2−t)2+b2(a2−t2)/a) T.theodor 2022.11.17.
(0,0) /2a =√a2t2+a2b2−b2t2/m2a2 T.theodor 2022.11.17.
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