f(x)=axn+bxn-1…+z α=1 f(x)=(x+α)(a’xn-1+b’xn-2…+z’) D<0 T.theodor 2022.12.3.
f(x)=axn+bxn-1…+z Δy/Δx=f’(α’)≠0 α=n’ g(x)=axn’+bxn’-1…+z ト same behavior T.theodor 2022.12.3.
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