Inequality of arithmetic and geometric means

Inequality of arithmetic and geometric means

{\frac  {x_{1}+x_{2}+\cdots +x_{n}}{n}}\geq {\sqrt[ {n}]{x_{1}\cdot x_{2}\cdots x_{n}}}\,,

 x1 = x2 = · · · = xn.

 

x+y/2 ≧  xy

x+y+z/3 ≧ 3 xyz

 

n=2k

 xn+y≧ 2xnyn ≧ nxy

n=2k-1

 xn+yn+z 3√xnynzn ≧ nxyz

 

{\frac  {x_{1}+x_{2}+\cdots +x_{n}}{n}}\geq {\sqrt[ {n}]{x_{1}\cdot x_{2}\cdots x_{n}}}\,,

 x1 = x2 = · · · = xn.

 

          T.theodor           2022.8.14