function - Turing のブログ

$y = ax 3$ $+bx 2$ $+cx+d$

$y = (x- -b- \sqrt b 2 -3ac /a 3a$ )(√ $a$ x+ $2b- \sqrt b 2 -3ac /a 6\sqrt a) 2$

$= (x- -b+ \sqrt b 2 -3ac /a 3a$ )(√ $a$ x+ $2b+ \sqrt b 2 -3ac /a 6\sqrt a) 2$

T.theodor 2022.10.1