2022-12-27 function f(x)=a'xn+b'xn-1…+z' f'(x)=a'xn-1+b'xn-2…+y'=t f'(x)=a'xn-1+b'xn-2…+y'−t=0 f(α')=f(β')=…=f(ω') T.theodor 2022.12.27.